log(1 + x)= x(1 + o(1))?

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What is the way to this transition? $NM*log⁡(1-\frac{U}{L(θ)}$$+o(\frac{log⁡(NM)}{NM}$$))$=$(-\frac{U}{L(θ)}$$+o(log⁡(NM))(1+o(1))$

N=M→∞

x=$-\frac{U}{L(θ)}$$+o(\frac{log⁡(NM)}{NM}$)→0

I thought: For |x|<1 :

$\frac{1}{1+x}=1−x+x^2−x^3+$…⟹Integrate both sides elementwise $log(1+x)=x−\frac{x^2}{2}+\frac{x^3}{3}−\frac{x^4}{4}+…=x+O(x^2)=x(1+O(x))=x(1+o(1))$

But I'm not sure?