Lottery: one bet with n numbers vs n bets with one number

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May someone help me with this probability problem, please?

In a lottery game, one random number between N numbers is choosen. One player chooses $n<N$ numbers in a single game. Other player chooses just one number for each $n$ games he plays. Question: Which player has the higher probability of winning the game?

Now what I know. First player probability of winning is : $\frac{n}{N}$

Probability of second player loses every game: ($1-\frac{1}{N})^n$

Probability of second player wins at least one game: $1-[(1-\frac{1}{N})^n]$

So, now I only need to prove that $\frac{n}{N}$ is higher or lower than $1-[(1-\frac{1}{N})^n]$ knowing that $N>n>1$, since for $n=1$ the probabilities are equivalent. I've tried and tried, but no success.

Also, I'm open to different solutions, but I'm in my third week of college, so I may understand only high school math.

Lastly, this is my first post in this forum and English is not my first language, so if there's something I did wrong, please tell me so I can change it.