I am trying to solve this task using Wolfram Notebook. I would like to know how new matrix is calculated (part b) after a change of basis.
Part a: I decided to show this part because part b is a continuation of part a
Basis for y=-x:
p := {{ 0, -1 },{-1, 0}}
30 degrees rotation:
RotationTransform[30*Degree, {0, 0}][{x, y}]
q is 30 degrees rotation as matrix:
q:={{Sqrt[3]/2, -2^(-1)}, {1/2, Sqrt[3]/2}}
a:=p.q
Part b
New basis:
w:={{1,-1},{-1,2}}
I did not understand how exactly change of basis works, however, I tried to implement what I learned in this video:
Inverse[w].p.w.a
This way seems to me not correct.
Question: How can I calculate new matrix representation after a change of basis?







New matrix representation after a change of basis: