The problem:..
Given two convex polygons $A$ and $B$, we can define Minkowski sum as A + B = {a + b: a $\in$ A, b $\in$ B}, where $a + b$ vector sum. Prove that:
every vertex $p \in A + B$ is a Minkowski sum of vertices of $A$ and $B$
Hint: Use the external perpendicular to $u$.
My attempt:
We could use that lemma:
for every external perpendicular u to an edge of A, there exists an external perpendicular to an edge of A + B, which will be parallel to u.
which I proved in another time.
Using the hint, let two adjacent edges $e,f$ of $A$ which meet at vertex $a$ have external perpendiculars $u,v$ (which are obviously not parallel; this would correspond to a discontinuity of the tangent to the perimeter in my previous suggestion, which ignores the hint you are given). Now use the lemma on these two edges and their external perpendiculars $u$ & $v$. All that remains is to argue that the corresponding edges in $A+B$ meet at a vertex. But wouldn't that have to be true if the images of $e$ & $f$ are connected and the corresponding external perpendiculars change from $u$ to $v$?