Consider a random variable $X$ with mean $0$ and variance $1$. Given $0 < d < 1$, do we have
$$E(e^{d X}) \leq 1 + O(d^2)$$
(it's true when $|X| \leq 1$)
Consider a random variable $X$ with mean $0$ and variance $1$. Given $0 < d < 1$, do we have
(it's true when $|X| \leq 1$)
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Consider $X \sim N(0,1)$.
We know that $\mathbb{E}[e^{dX}]=e^{d^2/2}$, which is clearly not $O(d^2)$. So the answer is no, based on this counter-example.