If I have a right $\triangle ABC$ with $B$ being the right angle and length $AB = 50$ and length $BC = 50$. Based on the Cartesian coordinate system if I wanted to move up the Y axis the length of the hypotenuse of this right triangle my book says I should calculate $\frac{\text{length}}{\sqrt{2}}$.
I don't understand the concept. I know the length of the hypotenuse of a right triangle is $\sqrt{2}$, but I don't understand the rationale behind dividing the length by $\sqrt{2}$ to find how many units up on the y axis to move.
EDIT. I forgot to include the position of the triangle. If the right $\angle B$ is at the coordinate $(0, 0)$. So side $AB$ is on the Y axis and side $BC$ is on the X axis.
EDIT. I apologize. I'm having trouble in understanding my homework. The question is how to calculate how many units up the Y axis to move if the hypotenuse length of a right triangle (ex. $50$)? My book says divide the hypotenuse by $\sqrt{2}$ but I don't understand why. Please disregard the length values in the first paragraph. All that is given is the hypotenuse length.