I know that given two power series, $A$ and $B$, such that $A= \sum_{n=0}^{\infty} a_n x^n$ and $B= \sum_{n=0}^{\infty} b_n x^n$ then,
$AB= \sum_{n=0}^{\infty} (\sum_{i=0}^{n}a_i*b_{n-i})x^n$
But then I was wondering, if $A$ is of the form $A= \sum_{n=0}^{\infty} a_n x^{mn}$ and $B= \sum_{n=0}^{\infty} b_n x^n$ for some $m \in [2,3,...]$ then,
Will the product of A and B, be
$AB= \sum_{n=0}^{\infty} (\sum_{i=0}^{n}a_i*b_{n-i})x^{mn}$
Hint: In the first formula, where did the exponent on $x$ come from? (Further hint: it's the sum of the indices of $a$ and $b$) Why?
Have you tried a concrete example, with finite power series (i.e., polynomials) and $m = 2$? For instance, have you checked out the case
$$ A = 3x^2 + 2 x^4 + 11 x^6 \\ B = 1 + 3x + 2x^2 $$ by explicitly comparing your two formulas?