Find the equation of the parabola with the vertex at the origin; directrix 2x = 3
So what I did is, find the equation of the directrix $$x = \frac{3}{2}$$ and then because its the directrix, the focus must be $$\bigl(-\frac{3}{2},0\bigr)$$ then multiplying it by 4, I get the equation $$y^2 = -6x$$ I'm correct right? because the book said the answer is $3y^2 = -8x$ and I've checked using graphing softwares that it isn't the same graph as my answer. Graphing softwares don't show the directrix so I can't confirm it. Although I've checked my answer and it seems odd that our textbook is wrong this time.