The question is- Points D and E divide equal sides AC and AB of an equilateral triangle ABC according to the ratio of : = : = : . Edges BD and CE meet at point O. Find ∠.
So, when I tried it, I have found out the following angles.
∠ACE= 40, ∠CDB=80, ∠COB=120, ∠COD=60, ∠ODA= 100,∠AEO=80 (I don't know how to put in the degree symbol) However, I can't seen to find the angle which is actually required. Can anybody help me with this?
You have found $\angle OCA= \angle ACE=40$
Consider the triangle $AOC$
Note that $\angle AOC = 180-\angle OCA-\angle OAC=180-40-30 =110$