Normal Distribution Quartiles

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lets say the first quartile of a random variable (continuous one) has a CDF function F such that $F(x) = .25$... e.g. the random variable is $3\times$ as likely to be larger than the first quartile than it is to be smaller?

What would the first quartile of $X$ be for $X\sim N(μ,σ^2)$?

Would it simply be $.25$ by symmetry of normal distributions?

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For $X\sim N(\mu,\sigma^2)$ the first quartile is

$$q_{0.25}=\sigma\cdot \Phi^{-1}(0.25)+\mu$$

where $\Phi$ is the CDF of the standard normal r.v. because $q_{0.25}$ is the solution of

$$P\{X\le q_{0.25}\}=P\left\{\frac{X-\mu}{\sigma}\le \frac{q_{0.25}-\mu}{\sigma}\right\}=\Phi\left(\frac{q_{0.25}-\mu}{\sigma}\right)=0.25$$