I have two games with different probabilities of winning. Let's say Game A has 80% of return to player percentage while Game B has 100% (which means a player will win no matter what). And there is a setting that I can adjust percentage to select game A or game B. Bpth Game A and Game B have 1/10 million odds to win Grand Jackpot.
Scenario 1: When I set up the game, I set up 50%/50% so I have 50% chance of selecting Game A and another 50% chance of selecting Game B. As it was mentioned above, the game A has 80% chance to win while Game B has 100% probability to win. So overall, I get 90% chance of winning (0.5 * 0.8 + 0.5 * 1 = 0.90).
Scenario 2: I set up my game as: 40% chance of selecting Game A and 60% chance of selecting Game B. I get total 92% chance of winning from both game packages now. (0.4 * 0.8 + 0.6 * 1 = 0.92).
So in this case, is my overall probability or odd of winning Grand Jackpot going to change between scenario 1 and scenario 2?? Does it matter when the odd for Jackpot is calculated separately for Game A and Game B? Hopefully this is clear question.
Any comments will be appreciated. Thanks
Yes, the overall probability of winning the Grand Jackpot is the same if you assuming that both games have a $1/10000000$ of winning the Grand Jackpot. You can compute it directly. Say $\alpha \in [0,1]$ is the probability of playing Game A.
Then the probability of winning the Grand Jackpot is $$ \alpha \times 1/10000000 + (1-\alpha) \times 1/10000000= 1/10000000.$$
In other words, it is still $1/10000000$ regardless of what $\alpha$ is.