Probability that a student misses the bus is $0.2$ (and is independent of whether or not he missed the bus previously). Over $5$ consecutive weekdays, what is the probability that he misses the bus on Tuesday and on two other days?
The answer I got was $0.03072$ Working:
$$0.2 \cdot \left[\binom{4}{2} \cdot 0.2^2 \cdot 0.8^2\right] = 0.03072$$
Is this correct? Thanks.