The question states:
Show that the line $y=kx+5$ intersects with the Parabola $y=kx+2$ for all values of k.
I thought this would be similar to the other problems where I use the discriminant but the answer ends up not being real... ?
I set them equal to each other,
$x^2+2=kx+5$
$x^2-kx-3=0$
$Δ=κ^2-4(-3)(1)$
Then I set this to 0 to find intersection, but it doesn't have a real intersection.
$k^2+12=0$
Any ideas?