Parametric equation of a rotated circle in 4 dimensions

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I'm attending a differential geometry course, and I'm stuck at one part of a question that we've been asked. The following rotated circle is given in 4 dimensions:

$$x_1x_3 + x_2x_4 = \frac{1}{2}$$

I need its 4-dimensional parameterization, using a $\phi \in [0,2\pi[$ value.

To show that this IS in fact a circle, you can solve the following system of equations to obtain their intersection:

$$ I. x_1^2 + x_2^2 + x_3^2 + x_4^2 = 1$$ $$ II. v = z \iff x_1 + ix_2 = x_3 + ix_4$$

Where I. is a 4-dimensional sphere, II. is a plane in 4 dimensions, with the correspondance of $$\mathbb{C}^2 \simeq \mathbb{R}^4$$ $$z := x_1 + ix_2$$ $$v := x_3 + ix_4$$ I'm including the calculation of this intersetion, just to give you a deeper understanding of the problem, however my question only extends to how to obtain the parametric equation of the above circle.

Note: The intersection of a 4-dimensional sphere and a plane can only give you a 2-dimensional circle, since by definition a 4D sphere is the collection of points equal distance from the origin. When we intersect the sphere with a plane, we apply this definition again, so we must get a circle.

Note 2: As far as I understand, this is a circle that's been rotated 45°'s in the $x_3$, and 45°'s in the $x_4$ direction.

Now I'll include the above mentioned calculation:

$$II. \Rightarrow x_3 = x_1 + ix_2 - ix_4 = x_1 + i(x_2 - x_4)$$ $$I. \Rightarrow x_1^2 + x_2^2 + (x_1 + ix_2 - ix_4)^2 + x_4^2 = 1$$ $$\Rightarrow x_1^2 + x_2^2 + x_1^2 - x_2^2 - x_4^2 + 2ix_1x_2 - 2ix_1x_4 + 2x_2x_4 + x_4^2 = 1$$ $$2x_1^2 + 2(ix_1x_2 - ix_1x_4 + x_2x_4) = 1$$ $$x_1^2 + x_1i(x_2-x_4) + x_2x_4 = \frac{1}{2}$$ Since in the first equation of this calculation we assumed that $$x_3 = x_1 + i(x_2 - x_4) \iff x_3 - x_1 = i(x_2 - x_4)$$ We can substitute to get rid of the imaginary unit: $$x_1^2 + x_1(x_3 - x_1) + x_2x_4 = \frac{1}{2}$$ $$x_1^2 + x_1x_3 - x_1^2 + x_2x_4 = \frac{1}{2}$$ $$x_1x_3 + x_2x_4 = \frac{1}{2}$$ And we get our original equation.

To get back to my original question, I've tried the parameterization of: $$C(\phi) = \biggl(\frac{1}{\sqrt{2}}cos(\phi),\frac{1}{\sqrt{2}}cos(\phi),sin(\phi),sin(\phi)\biggr), \phi \in [0,2\pi[$$ But after a long while of calculation it ended up being wrong, because I've got nonsense. So dear Stack Exchange users, can you help me figure this one out?

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The single equation you wrote at the beginning does not describe a circle, but a $3$-dimensional object. However, your own proof shows that the following is a circle:

$$ x_1x_3+x_2x_4=\frac12,\ x_1=x_3,\ x_2=x_4. $$

Or to write it even more simply

$$ x_1^2+x_2^2=\frac12,\ x_1=x_3,\ x_2=x_4. $$

In other words, you forgot the equality constraints. This should now not be a problem to parametrize.