So I am familiar with finding the parametric equation given multiplicative $x$ and $y$ values but in a problem such as
$x=2+\cos(t)$,
$y=3+\sin(t)$,
$0\le t \le \frac{5\pi}{2}$
I cannot even make of what I am supposed to do to find what type of graph this will be on nor its direction.
community wiki post so that the question can be closed
To expand on what was said in the comments, we have \begin{align*} x & = 2 + \cos t\\ y & = 3 + \sin t\\ \end{align*} where $0 \leq t \leq \frac{5\pi}{2}$.
We eliminate $t$. \begin{align*} x - 2 & = \cos t\\ y - 3 & = \sin t \end{align*} Squaring each equation and adding yields $$(x - 2)^2 + (y - 3)^2 = \cos^2t + \sin^2t$$ Using the Pythagorean Identity $\cos^2t + \sin^2t = 1$ yields $$(x - 2)^2 + (y - 3)^2 = 1$$ which is the equation of a circle with radius $1$ and center $(2, 3)$. For the entire circle to be traversed, the interval in $t$ must have length at least $2\pi$. Since $\frac{5\pi}{2} > 2\pi$, the entire circle is traversed. In fact, it is traversed $$\frac{\frac{5\pi}{2}}{2\pi} = \frac{5\pi}{2} \cdot \frac{1}{2\pi} = \frac{5}{4}$$ times.