Isn't it wrong to write the following with only the percent sign? Instead of $100 \%$?
The change in height as a percentage is $$ \frac{a - b}{a} \% \tag 1 $$ where $a$ is the initial height and $b$ is the final height.
Because if $a=10$, $b=5$ we have $$ \frac{10-5}{10}\%=\frac{1}{2} \% = 0.5 \frac{1}{100} = 0.005 \quad \text{what?!} \tag 2 $$
If we convert a decimal number to percent we multiply it by $100$ and add the percent sign. We have $1\%=\frac{1}{100}$, so with $100 \%$ we multiply the number by $1$, i.e. \begin{align} \frac{10-5}{10} \cdot \color{blue}{1} &= \frac{10-5}{10} \cdot \color{blue}{100 \%} = \frac{5}{10} \cdot \color{blue}{100 \frac{1}{100}} =\frac{1}{2} \cdot \color{blue}{100 \frac{1}{100}} \tag 3 \\ &=0.5\cdot \color{blue}{100 \frac{1}{100}} =50 \color{blue}{\frac{1}{100}} = 50 \color{blue}{\%} \tag 4 \end{align} So, shouldn't we instead write $(1)$ as $$ \frac{a - b}{a} 100 \% \quad ? \tag 5 $$
In what concerns exclusively the use of the percentage sign $\%$, it is simply a shorthand notation for $1/100$, so e.g. five percent of a population of $n$ elements is equivalently expressed as the amount $$n \cdot 5\%=n\cdot \frac{5}{100} =\frac{n}{20}= 0.05 n$$
So it is true that $$\frac{10-5}{10}\%=\frac{1}{2}\%=0.005$$ although it certainly doesn't correspond to the percentage representation of the ratio $\frac{1}{2}$, which would of course be $50\%$.