If the perimeter of a rectangle is $160$ meters and its area is $1200$ square meter, then one of its sides must be __________ the other side.
My approach to this question is:
$$x=\text{one side}$$
$$y=\text{other side}$$
$$x+y+x+y=160$$
$$x\times{y}=1200$$
$$2(x+y)=160$$
$$x=80-y$$
$$x\times{y}=1200$$
$$(80-y)\times{y}=1200$$
$$y^2+80y-1200=0$$
Am i going in right direction? If yes, then I stuck at this point. Any help will be highly appreciated.
Thanks and Regards
Sumaira