I'm having some trouble with planar graphs. Two questions I was stuck on were:
Prove that each planar graph on $n \gt 3$ vertices will have a minimum of $4$ vertices of degree $5$ at most.
Let's say you are provided a planar graph on $17$ vertices and that there is a drawing of such a graph with $17$ faces (countries). Prove that such a graph has vertex with degree $3$ or less.
I ended up using a proof by contradiction. For (1), I showed multiple cases. For (2), I solved for the number of edges then assumed to the contrary that all vertices are of degree 4.