poker probability question not sure

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i am confused with what does the question mean drawing two cards showing same number from one suite?

i figured it would be: 13C2 * 4C1 * 4C1 * 31C4 / 53C5?

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The normal definition of two pairs does not mention suits at all. You just need two each of two different numbers, like $2,2,4,4,5$. You can't have two cards with the same number and suit because there is only one of each card in the deck. I would read it that they are requiring that the fours have the same two suits as the twos, but that is not usually required.