Posterior from Gamma

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Suppose the prior for $μ$ is $Gamma(k,λ)$, so $fμ(m)=Cm^{k−1}exp(−λm)I(m≥0)$.

Further, suppose the data $X_1,…,X_n$ given $μ$ is iid Poisson with parameter $μ$, so for each $[Xj∣μ=m]∼[X∣μ=m]$, $f_X∣μ=m(i)=exp(−m)m^i/i!I(i∈{0,1,…})$,

How can I show that the posterior for μ is also Gamma? Would the parameters of the Gamma be a function of $k$ and $\lambda$?

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The prior is

$$\pi(\mu)\propto \mu^{k-1}e^{-\lambda\mu}$$

The likelihood is

$$p(\mathbf{x}|\mu)\propto e^{-n\mu}\mu^{\Sigma_i x_i} $$

Thus the posterior is

$$\pi(\mu|\mathbf{x})\propto \pi(\mu)\cdot p(\mathbf{x}|\mu) =\mu^{(k+\Sigma_i x_i)-1}e^{-(\lambda+n)\mu}$$

Thus the posterior is still gamma with parameters

$$Gamma(k+\Sigma_i x_i;\lambda+n)$$

Hint: to simplify the calculations it is suggested to waste any quantity that doesn't depend on $\mu$