I would like to know if the following affirmation is true or not: If M is a set of consecutive natural numbers there is a prime number in the factorization of one of M's elements that doesn't divide any other element in the set.
2026-02-23 12:05:45.1771848345
Prime numbers in factorizations of natural numbers
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For the original question, where the word consecutive was not included: It is not true. Take $M=\{6,10,15\}$