Given $A$, $B$ and $C$ where $A$ and $B$ are mutually exclusive.
If $P(A\cap C)=0.2$, $P(B\cap C)= 0.1$, $P(C)=0.6$, $P(A\cup B)= 0.6$, $P(A\cup C)= 0.8$, and the relation $P(A) = 2P(B)$, find the probabilities of $A$ and $B$.
Given $A$, $B$ and $C$ where $A$ and $B$ are mutually exclusive.
If $P(A\cap C)=0.2$, $P(B\cap C)= 0.1$, $P(C)=0.6$, $P(A\cup B)= 0.6$, $P(A\cup C)= 0.8$, and the relation $P(A) = 2P(B)$, find the probabilities of $A$ and $B$.
Hint: Since $A,B$ are mutually exclusive, then $P(A\cup B)=P(A)+P(B).$