I've to prove that following is true:
$$\mathsf P(a,b,c,d)=\mathsf P(b,c)\mathsf P(d|a,b,c)\mathsf P(a|b,c)$$
I've been tried to split or plug some part but I can't get nothing .
2026-04-02 16:51:04.1775148664
Probability - Bayes' Theorem with multiple random variables
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