For this question, I don't understand the highlighted part of the solution
I thought it should be >5, but then 6?
2026-04-07 10:57:51.1775559471
probability: Chebyshev inequality question
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Note that $\log_2R$, and hence $|\log_2R-80|$ are integers. Therefore, the complement of the event $|\log_2R-80|\le 5$ is the event $|\log_2R-80|\ge 6$.