Probability Distribution Table of Bus Arrival

Question

For an assignment in my high school Data Management class, I am required to make a probability distribution table for my data, which is "Wait Time for a Bus." It is not just any bus. It is a specific bus that arrives at a bus stop near my school, and I know someone who takes this bus, so I ask her to record the data down for me.

This bus is supposed to arrive at 12:15 pm every day, but sometimes its a little late or a little early, and sometimes its on time.

I have gathered the data and timings for the past 20 days.

Now, what I believe I should do is that I should arrange my data in ascending order and group them in ranges. To find the probability, my classmate said to do "Success over total." I think she means the total number of outcomes. This is what I`ve been told by a classmate, at least, this is what she is doing, and to be honest, what she told me sounds a little confusing because she did not elaborate on it.

Here is my organized data set in ascending order: -4, -4, -4, -3, -3, -2, -2, -1, 0, 0, 0, 0, 0, 0, 0, 1, 1, 2, 3, 5.

I am quite confused on how to do this, and I`ve asked around as well, but I am not getting quick responses. Am I on the right track? Is what my classmate told me to do right?

THIS PART HAS BEEN EDITED

This is what I did for the probability distribution table (click the Probability Distribution Table to view the table if you cannot view it on here):

NEWLY EDITED

I have done the continuous probability distribution graph (the y-axis is the probability, and the x-axis is the wait time for the bus in minutes). Although, to me, does not look right. Im pretty sure this is how the continuous probability distribution with a normal distribution curve is supposed to look like, considering Ive searched up and seen some things similar to what I have done.

Answer 1

You populated the distribution table correctly so yes, you are doing it right. You can understand "success over total" as the probability. A more formal way to understand it would be as below $$ \text{Probability of something happening} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} $$

Answer 2

Now that you have binned the data, all you need to do is to divide the size of each bin by the total number of observations. In your example, there are 20 observations. There are 3 entries in the -4 bin, so the probability of the wait time being -4 = 3/20. And so on.

The choice of bins is somewhat arbitrary. For example, you could have created coarser bins of the type -4:-2, -1:1, etc. Or finer bins with higher resolution, though in your example that wouldn't be meaningful because your data resolution is 1 minute.

To summarize, just think of the probability distribution as the histogram normalized by the total number of observations.