A clerk at a convenience store leaves her counter unattended at 3:02 PM. When she returns at 3:08 PM, there is an impatient customer waiting at the counter. Given that the impatient customer did not arrive in the first 2 minutes, what is the probability that he arrived in the last 2 minutes of this interval?
Is there even a method to do this. Because there should be information about mean or the type of distribution. Or am i missing something?
the interval of unattended counter is 6 minutes long, that is the union of 3 equal intervals of 2 minutes long.
Given the fact that in the first 2 minutes nobobody arrived, the probability that the customer arrived in the last 2 minutes is $\frac{1}{2}$
EDIT: assuming uniform distribution of arrival times