Probability equations

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I need to proof that

$$P[\varphi] \le P[\psi]\text{ does not imply }P[\varphi\rightarrow\psi] = 1 $$

$$P[\psi] + \varepsilon ≥ P[\varphi]\text{ does not imply }P[\varphi\rightarrow\psi] \ge 1− \varepsilon$$

$$P[\varphi] = P[\psi]\text{ does not imply }P[\varphi\leftrightarrow\psi] = 1 $$

I have the following information

$$ \operatorname{Pr}[\varphi]=\sum_{\beta \in Q,\ \beta | \models \varphi} p(\beta) $$

Any advice?

Actual state:

For the first I have at the moment

$$P(A) = P(B)$$

$$P(A|B) = P(B|A)$$

$$\frac{P(A \wedge B)}{P(B)}=\frac{P(A \wedge B)}{P(A)}$$