Probability of $A \cup A$

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Studying for an exam and just want to check this "degenerate" case.

I know in boolean algebra, A + A = A. So I assume that same would hold true in set notation. My proof is as follows:

$P(A \cup A) = P(A) + P(A) - P(A \cap A) = P(A)$

I couldn't find this anywhere else but just wanted to double check here.

As a sidenote, I guess this means that $P(A \cap A) = P(A \cup A) = P(A)$?

Thanks so much.