Probability of drawing a card from suit giving n cards already drawn and some of them unknown

Question

Say you have 15 cards already drawn, of which you know five and four of these five are of the same suit, what is the probability of drawing a card of the same suit as of the four from the remaining 37 cards?

Any references or solution roadmap are appreciated.

Answer 1

Any card you pick could be one of $9$ of the same suit out of $47$ unknown cards. The other $10$ cards are a red herring inserted to confuse the student.

$$P = \frac{9}{47}$$

Answer 2

Assume you know 9 cards so 43 are left. There are still 9 of the suite. So 9/43.

Answer 3

We don't know the remaining 10 cards so we can assume we have 47 cards to drawn from and we have nine cards of that suit so

P(A) =9/47