what is the probability of drawing exactly 4 diamonds out of a full set of playing cards on 10 tries? no replacement.
i have done this:
$$P(X=0)=\binom{10}{4}\left(\frac14\right)^{10}\left(1-\frac14\right)^6 = 3.56 *10^{-5}$$
anyways, i feel my answer is wrong. ... Am i at least doing something right here?
"probability of drawing exactly 4 diamonds of a full set of playing cards on 10 tries", unless otherwise specified, always implies drawing without replacement,
$$\text{so using the hypergeometric distribution,}\;\;Pr = \frac{{13\choose 4}{39\choose 6}}{52\choose 10}$$