If i have a stripped deck consisting of only $3$ suits instead of all $4$ suits, what is the probability I am able to make a full house?
I am not sure where to begin but I have the following
$${_{13}C_1}\cdot{_3C_3}\cdot {_{12}C_1}\cdot{_3C_2}=468$$ possible combinations
$$\frac{468}{{_{39}C_5}} = 0.0812\%$$
Any help would be appreciated.