If theres 48 in a deck and 24 of them are red and 24 of them are black. Whats the probability that the next card is red, when 4 out of 12 cards drawn are red without replacement?
Does the success rate(4/12, 33%) influence what the next card drawn will be ? i.e. How would you go about this ?
If the deck is shuffled properly, the chance of any card that is drawn will only be affected by how many of each colour are left in the deck. The fact that that you've drawn four red cards only affects the probability in that there are four fewer red cards in the deck.
If you've drawn 12 cards and four of them are red, then 8 are black. Therefore there are 36 cards left, 20 of which are red and 16 of which are black. So the probability of drawing a red card next is $\frac{20}{36} = \frac{5}{9}$.