Proof for $\bigwedge_{n=1}^\infty\bigvee_{k=n}^\infty x_k = \limsup x_n$

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How I can show the truth of this relationship?

$$\bigwedge_{n=1}^\infty\bigvee_{k=n}^\infty x_k = \limsup x_n$$

The definition of $\limsup x_n$ is $$\limsup x_n = \inf_n\left[\sup_{k\ge n}x_k\right]$$