I wanted to conclude Fermat's Little theorem form below fact.I had proved following facts but unable to conclude result
Let F be finite field with char $p\neq 0$ then $f:F\to F$ such that $f(x)=x^p$ is automorphism
Also I know that any field automorphism is identity on prime subfield
How can above 2 facts leads to proof that
For $a\in \mathbb Z$
$a^p-a=0\mod p$
Any Help Hint will be appreciated
Well, ${\Bbb Z}_p$ is the prime field of characteristic $p$. The mapping $x\mapsto x^p$ is an automorphism of ${\Bbb Z}_p$ and the prime field is fixed under an automorphism. It follows that $x^p=x$ for each element $x$ of ${\Bbb Z}_p$, which is equivalent to $x^p\equiv x\mod p$.