Proof that $P(\limsup_{n\to \infty} A_n) = 0$ - isn't it equal to $P(A_n)$?

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For the question to be more understandable, here is a link for a screenshot:

the exercise

Using the definition from below the to be proven statement, I have come to the following conclusion:

$\limsup_{n\to \infty} A_n = \cap_{n\ge 1} (\cup_{k\ge n} A_k) = (A_1 \cup ... \cup A_n) \cap (A_2 \cup ... \cup A_n) \cap ... \cap (A_n \cup A_n) = A_n$ therefore $P(\limsup_{n\to \infty} A_n) = 0$ only if $P(A_n) = 0$.

Is that correct or have I made some logical error here, it doesn't say anywhere in the exercise that $P(A_n) = 0$.

I'd be very glad if one of you could help me with this and also send me some formatting cheat sheet for this website so the questions can get easier to read.