Just came from an exam and I am wondering how to prove the following:
A topological space $X$ is connected if for each continuous function $f:X\rightarrow X$ there is a $x \in X$ such that $f(x)=x$.
Just came from an exam and I am wondering how to prove the following:
A topological space $X$ is connected if for each continuous function $f:X\rightarrow X$ there is a $x \in X$ such that $f(x)=x$.
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Let us show that the contrapositive holds. If $X$ is not connected, then $X=U\cup V$ for some disjoint open non-empty subsets $U$ and $V$. Pick $u$ in $U$ and $v$ in $V$. Can you think of a continuous function $f:X\to X$ using $u$ and $v$ and such that $f(x)\ne x$ for every $x$ in $X$?
One way to ensure this condition would be that $f(x)\in V$ for every $x$ in $U$ and that $f(x)\in U$ for every $x$ in $V$. But remember, $f$ must be continuous... Last hint: one can do this with $f(X)=\{u,v\}$.
Exercise: Find some connected $X$ and some continuous $f:X\to X$ with no fixed point (thus the reverse implication does not hold).