Can anyone please explain how $$\exp[y/\alpha]=\exp[y-\log\alpha]$$ ?
I tried as :
$$\exp[y/\alpha]=\exp(y/\exp[\log\alpha])=?$$
I think $$\exp(y)\exp[-\log\alpha],$$ can be written as $$\exp[y-\log\alpha].$$
But not $$\exp(y/\exp[\log\alpha]),$$ can be written as $$\exp[y-\log\alpha].$$
The left-hand side should read $\exp(y)/a$
Can you take it from there?
$$\exp(y)/a=\exp(y)/\exp(\log a)=\exp(y-\log a)$$ On the other hand, $$\exp(6/3)=\exp(2)=e^2=7.389\\ \exp(6)/3=(e^6)/3=403.429/3=134.476$$