prove if $E_{1},E_{2},...,E_{n}$ are independent events then $p(\cup_{i=1}^{n}E_{i})=1-\prod_{i=1}^{n}[1-p(E_{i})]$

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prove if $E_{1},E_{2},...,E_{n}$ are independent events then:

$p(\cup_{i=1}^{n}E_{i})=1-\prod_{i=1}^{n}[1-p(E_{i})]$

my try: $$ p(\cup_{i=1}^{n}E_{i})=1-p((\cup_{i=1}^{n}E_{i})^{c})=1-p(\cap_{i=1}^{n}E_{i}^{c}) =1-\prod_{i=1}^{n}p(E_{i}^{c})=1-\prod_{i=1}^{n}[1-p(E_{i})] $$ $E_{1},E_{2},...,E_{n}$ are independent,

so i guess $E_{1}^c,E_{2}^c,...,E_{n}^c$ are also independent

(I need to prove it but got little confused with all the Inclusion-Exclusion principle)

Would appreciate any help :)