Let $X_1, X_2, \ldots$ be i.i.d. random variables with mean $\mu$ and variance $\sigma^2$. How does
\begin{equation} \mathbb E\left[\,\left|\frac{1}{N} \sum_{i=1}^n X_i - \mu\, \right|\,\right] \to O\left(\frac{1}{\sqrt N}\right) \end{equation}
follow from the central limit theorem? We easily get
\begin{equation} \mathbb E\left[\left(\frac{1}{N} \sum_{i=1}^n X_i - \mu\, \right)^2\right] = \frac{\sigma^2}{N}, \end{equation}
but how to get the first one?
EDIT: Actually, any proof would do $-$ does not have to use the central limit theorem.
Since $r\mapsto(\mathsf{E}|\cdot|^r)^{1/r}$ is nondecreasing,
$$ \mathsf{E}|\bar{X}_N-\mu|\le \frac{\sigma}{\sqrt{N}}. $$