Let $T, S$, linear transformations which are simultaneously diagonalizable. Prove that $T+S$ is diagonalizable.
I need to rely on the the definition: $T,S$ are called simultaneously diagonalizable if there is a basis of $V$ composed by eigen-vectors of both $S$ and $T$.
I'd be glad for a direction.
Thanks.
Hint: Suppose that $PTP^{-1}$ and $PSP^{-1}$ are diagonal. $$ P(T + S)P^{-1} = PTP^{-1}+PSP^{-1} $$
"How to bounce:" for a vector $v$ in our common basis of eigenvectors, $$ (T + S)v = Tv + Sv $$