How do I show that $x^{2n} + y^{2m} = 1$ has a domain of $|x| \leq 1$? How would I show the opposite, that $$x^{2n-1} + y^{2m-1} = 1$$ has a domain covering all real values?
2026-04-19 21:08:54.1776632934
prove $x^{2n} + y^{2m} = 1$ is a "closed" shape
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