Consider the function
$$\frac{x}{C-x} \quad (C\in\Bbb R \ \text{a constant}).$$
C>=0
How can I prove that it is a convex function?
or this $$\frac{x}{10-x}$$
Consider the function
$$\frac{x}{C-x} \quad (C\in\Bbb R \ \text{a constant}).$$
C>=0
How can I prove that it is a convex function?
or this $$\frac{x}{10-x}$$
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Your function is undefined at $x=C$. In all other places, show that $f''(x)>0$. Arithmetic may be easier if you prove $$f(x) = \frac{C}{C-x} - 1$$