Proving triangle congruence

Question

I have been tasked to prove the following: $$\triangle ABC \cong\triangle EDC $$ Give that $C$ is midpoint of $\overline{BE}$, and angles $\angle B $ and $\angle E$ are right angles.
How would you approach in proving the congruence?
P.S Drawing is not accurate representation

Answer 1

Hint: you know the length of a side and two angles in both triangles.

$\angle B = \angle E$

$|BC|=|CE|$

Then you'll just need to argue that: $\angle ACB = \angle ECD$

Answer 2

Here, $$\angle ACB=\angle ECD~~~[\text{vertical angle}]$$ $$\angle ABC=\angle CED=90^{\circ}$$ $$BC=CE~~~[\text{As,C is the midpoint of BE}]$$ So, $$\triangle ABC \cong\triangle EDC$$