Proving triangles congruent with circles

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I have a proof that looks like the following, not really sure where to start/how to solve. Any help would be appreciated.

Given: circle $S$ and circle $T$ intersect at $M$ and $O$. Prove: $\triangle MST \cong \triangle OST$

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First, note that the side ST is common to both triangles so you have a side in common.

Next, consider what you know about the lengths of SM and SO. What about the lengths of MT and TO? They both are the radius of the circles. Then you could use the Side-Side-Side to show congruence. Perhaps there is another way to use the angles here for an alternative but this seems rather straightforward if S and T are the center of each circle.