If $T : V^6 \rightarrow V^4$ is a linear transformation
And, It can not be one-to-one.
Let $A$ be a matrix representation of $T$
Then
$T$ is onto if and only if columns of $A$ span $V^4$
This is definition.
My question is we know that there are 6 columns.
Out of these 6 columns, as long as 4 are independent, then Is it onto ?
Yes, because if four of them are independent, they will form a basis for $V^4$