Question is:
$f(x,y)=e^{(-x/y)}e^{-y}/y$ when $x>0, y>0$
it equals to 0, otherwiseWhat is $f_{X}(x)?$
I think: $f_{X}(x)= \int^{∞}_0f(x,y)dy = \int^{∞}_0 e^{(-x/y)}e^{-y}/y dy$
Then I should consider y as a variable,
x as constant.
but it seems I can't separate x, y. Since the term is
$ e^{[-(x+y^2)/y]} /y dy$
if we consider
$ (e^z)' = e^z $ seems not working easily here,
since we have
$z = [-(x+y^2)/y]$
Then it still needs to consider $z'$ into this equation...
I really really stuck on here.
Is there anyone could help me?
Many thanks!