Rayleigh-Bénard convection

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I have a nondimensionalized linear perturbation system relevant to the appropriate pure conduction solution for Rayleigh-Bénard convection in upper planetary atmospheres under the compressible gas version of the Boussinesq approximation: $$ \frac{\partial u}{\partial x} + \frac{\partial w}{\partial z} = 0\\ \frac{\partial u}{\partial t} = -\frac{\partial p}{\partial x} + (m\frac{\partial^2}{\partial x^2} + \frac{\partial^2}{\partial z^2})u\\ \frac{\partial w}{\partial t} = -\frac{\partial p}{\partial z} + R\theta +(m\frac{\partial^2}{\partial x^2} + \frac{\partial^2}{\partial z^2})w\\ \frac{\partial \theta}{\partial t} = w + (m\frac{\partial^2}{\partial x^2} + \frac{\partial^2}{\partial z^2})\theta\\ w = \theta = \frac{\partial u}{\partial z} + \frac{\partial w}{\partial x} = 0 \text{ at } z = 0,1 $$ Here the gas has perturbation velocity components $(u,v)$, reduced pressure $p$, and temperature $\theta$ which are functions of the spatial coordinates $(x,z)$ and time $t$. Further, $R$ is the compressible fluid Rayleigh number and to account for the role of eddies an eddy kinematic viscosity and thermometric conductivity, which are assumed equal, have been introduced where $m$ is the ratio of the horizontal to the vertical diffusivity.

Seeking a normal mode solution of this system of the form: $$ u(x,z,t) = A\sin(nx)\cos(\pi z)e^{\sigma t}\\ [w,\theta](x,z,t) = [B,C]\cos(nx)\sin(\pi z)e^{\sigma t}\\ p(x,z,t) = D\cos(nx)\cos(\pi z)e^{\sigma t} $$ obtain the secular equation $$ k_1^2\sigma^2 + 2k_1^2k_m^2\sigma + k_1^2k_m^4 - n^2R = 0 $$ where $$ k_m^2 = mn^2 + \pi^2 = \pi^2(1 + \frac{4m}{\lambda^2}) \text{ for } \lambda = \frac{2\pi}{n} $$ I'm not quite sure on where to begin. All of the other parts of the question are fairly simple, but this one is stumping me completely. I'd really just need a little help getting pointed in the right direction, if that wouldn't be too much to ask for.

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Substitute the normal mode solution into the partial differential equations. The boundary conditions at $z = 0,1$ are already satisfied.

This leads to the following homogeneous system of algebraic equations for $A$, $B$, $C$, and $D$.

$$nA + \pi B = 0\\(\sigma + k_m^2)A - nD = 0\\ (\sigma + k_m^2)B -RC - \pi D = 0\\-B + (\sigma + k_m^2)C = 0.$$

A solution is obtained when the determinant of this system equals zero -- generating the secular equation.

$$\begin{vmatrix}n & \pi & 0 & 0 \\ \sigma + k_m^2 & 0 & 0 & -n \\ 0 & \sigma + k_m^2 & -R & -\pi \\ 0 & -1 & \sigma + k_m^2 & 0\end{vmatrix}= 0$$

Expanding the determinant leads to

$$n^2[(\sigma+ k_m^2)^2 -R] + \pi^2 (\sigma + k_m^2)^2 = 0,$$

which can be rearranged into your form:

$$(n^2+\pi^2)\sigma^2 + 2(n^2+\pi^2)k_m^2\sigma+ (n^2+\pi^2)k_m^4-n^2R = 0.$$

With $k_1^2 = n^2 + \pi^2$ this is

$$k_1^2\sigma^2 + 2k_1^2k_m^2\sigma+ k_1^2k_m^4-n^2R = 0.$$