Rearranging exponential functions

159 Views Asked by At

Using two different strategies, I've derived an equation for a particular function $f(\phi)$. That equation is

$$ f(\phi)=\frac{1}{1-e^{-T\gamma}}(1-e^{-T\gamma\phi}). $$

However, the paper whose result I'm trying to replicate is telling me that the function is

$$ f(\phi)=(1-e^{-\gamma})(1-e^{-\gamma\phi}). $$

Is there a way to rearrange the result I got so that it matches the result in the paper?

EDIT:

What's confusing me about this is that the function needs to be such that $f(0)=0$ and $f(1)=1$. This is true of the equation I derived. But for the equation in the paper, $f(1)=1$ only if $\gamma=\ln(1/2)$, which is not the case in the specific example given later in the paper. So something weird is afoot (either on my part or on the paper's).

1

There are 1 best solutions below

3
On BEST ANSWER

The functions are not the same. My test: set each variable to 3 ($\gamma=3, \phi=3,T=3$) and evaluate. Your function evaluates to $f(3) = 1.000123425$. The paper's function evaluates to $f(3) = 0.950095666$.