Let $E$ denote a compact metric space. Let $T$ denote the non-negative reals. Let $E^T$ denote the class of all functions from $T$ to $E$. Let $C$ denote the subset of $E^T$ consisting of càdlàg functions (i.e. continuous from the right, limits exist from the left).
On $C$ we can define the Skorokhod metric; and this metric induces the corresponding Borel sigma algebra.
On the other hand, we have the usual product sigma algebra on the space $E^T$, and restricting this sigma algebra to $C$ in the natural way yields a second sigma algebra on the space $C$.
My question is this: Is there any relation in size (with respect to inclusion) of these two sigma algebras defined on $C$.
Many thanks for your help.
Proposition 7.1 in Chapter 3 of Markov Processes: Characterization and Convergence by Stewart N. Ethier and Thomas G. Kurtz says the following: $${\cal B}(D_E[0,\infty)) \supset \sigma(\pi_t: 0\leq t<\infty) $$ with equality when the metric space $E$ is separable.