Can the heaviside step function, $u(t)$ be represented like so:
$$u(t)=\frac{1}{2}\left(\frac{|x|}{x}+1\right)$$
Can the heaviside step function, $u(t)$ be represented like so:
$$u(t)=\frac{1}{2}\left(\frac{|x|}{x}+1\right)$$
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Since $$\frac{|x|}{x}=1, (x>0),~~=-1, (x<0)$$ so it can be written as $u(x)=\frac{\text{sgn}(x)+1}{2}$ which shows the Heaviside Function. It is said that: